[rc5] key security question

Benedikt Eric Heinen beh at icemark.ch
Fri Jun 6 00:49:01 EDT 1997

> >Think keyspace: for each first key you have to search all the 2^56 second
> >keys. This makes 2^112 combinations, IOW a 112-bit key. This presumes that
> Not true, the work is 2^56 for each, for 2^57 total.

Hmm, well - if I just look at what a brute-force approach has to do, I
think 2^57 is wrong. For single encryption, we'll have to check 2^56 keys.
For double encryption this should mean having to check 2^56*2^56 keys i.e.
2^112 keys - yeah, it looks like it would be 2^112 keys...



          Hiroshima '45           Chernobyl '86           Windows '95

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